EXAMPLE 10 : ------------------------------------------------------------
:
:Saatcioglu and Razvi for normal-strength concrete
:
SYSTEM:
S=0 T=0  E=1  C=2  P=1  TOL=0.0001 : 
:                                
SECTION:
1  S=1  HI=24   HJ=24   N1=12   N2=12   X=0   Y=0 :  24"x24" Column
:                                                12x12 mesh
:
CONFINED:
14   F=14,10,10,1 ,12 :
:
STEEL:
1    X=   2.5  Y=   2.5  A=0.79   T= 1 :  Long. Steel Type
3    X=  21.5  Y=   2.5  G= 1, 3       :  8 #8 Bars
5    X=  21.5  Y=  21.5  G= 3, 5       :  2 in. clear cover to bars
7    X=   2.5  Y=  21.5  G= 5, 7       :  assume #4 hoops
8    X=   2.5  Y=  12.0                :
:
PROPERTY:
I=5 FC=4.35 E1=0.0018 E2=0.0035 FR=0.4 : E2 Based on 0.85f'c
I=5 X=2,0.155 Y=5,0.155 1=8.32,6.89 2=28.0,6.65 S=3.15 T=60 R=0.4 M=0.2 : CONF.
SY=2:    SY=1 for design steel stress-strain (FY=60 KSI and E=29000 KSI)
:             SY=2 for probable steel stess-strain (FY=68 KSI, FU=100 KSI and E=29000 KSI)
:
DATA:
 EC=0.0002
 EC=0.0004
 EC=0.0006
 EC=0.0008
 EC=0.0010
 EC=0.0015
 EC=0.0020
 EC=0.0025
 EC=0.0030
 EC=0.0035
 EC=0.0040
 EC=0.0050
 EC=0.0060
 EC=0.0070
 EC=0.0080
 EC=0.0090
 EC=0.0100
:
END:
