EXAMPLE 11 : ---------------------------------------------------------
:
: T-section with non-linear strain distribution 
SYSTEM:
 T=0  P=1  E=1  C=1  TOL=0.0001  M=0  : M=1 for Negative Moment-Curvature 
:
SECTION:
 1  HI=10  HJ=22  N1=5   N2=11  X=12  Y=0   : 10"X22" Web
 2  HI=34  HJ=8   N1=17  N2=4   X=0   Y=22  : 34"X8"  Flange
:
STEEL:
  1  X=14.5  Y=2.5    A=0.79  T=1   : 
  3  X=19.5  Y=2.5    G=1,3            : 
  4  X=14.5  Y=27.5                 :
  6  X=19.5  Y=27.5   G=4,6         :
  7  X=4       Y=24.5   A=0.79  T=1   : l 
  8  X=8       Y=24.5                 : 
  9  X=26     Y=24.5                 :
 10  X=30    Y=24.5                 :
 11  X=4      Y=27.5                 :
 12  X=8      Y=27.5                 :
 13  X=26    Y=27.5                 :
 14  X=30    Y=27.5                 :
:
PROPERTY:
 I=1 FC=4  E1=.002  E2=.004  FR=.4     : Unconfined Concrete
                                                               : Blank Line for Confined
 FY=68  FU=100  FF=95   E1=.004 E2=.08 E3=.12  E=29000  ET=1200
 FY=45  FU=70   FF=65   E1=.030 E2=.12 E3=.20  E=29000  ET=1100
:
STRAIN:
E=1 NI=6:          
X=0  FR=.1:                 
X=6  FR=.5:                 
X=13 FR=1:                
X=21 FR=1:                 
X=28 FR=.5:               
X=34 FR=.1:                
:
DATA:
 EC=0.0002  A=0  P=0  : Moment about Global X-Axis
 EC=0.0004  A=0  P=0  : No Axial Load
 EC=0.0006  A=0  P=0
 EC=0.0008  A=0  P=0
 EC=0.0010  A=0  P=0
 EC=0.0015  A=0  P=0
 EC=0.0020  A=0  P=0
 EC=0.0025  A=0  P=0
 EC=0.0030  A=0  P=0
 EC=0.0035  A=0  P=0
 EC=0.0040  A=0  P=0
 EC=0.0050  A=0  P=0
 EC=0.0060  A=0  P=0
:
END
