EXAMPLE 5 : ------------------------------------------------------------

SYSTEM:
S=0 T=1  E=1  C=2  P=1  TOL=0.0001 : T=1 for P-M Diagram
:                                 P=1 to check stress-strain
:                                 C=2 all concrete is confined at rebar 
:                                 E=1 do not allow any rebar to fracture
:
SECTION:
1  S=1  HI=24   HJ=24   N1=12   N2=12   X=0   Y=0 :  24"x24" Column
:                                                12x12 mesh
:
CONFINED:
N1=14   NX=10  NY=10  NI=1  NJ=12 : N1 no. of the first confined element
                                                            : NX no. of confined elements in the X-direction
			            : NY no. of confined elements in the Y-direction
			            : NI  increment in X-direction
			            : NJ increment in Y-direction			
:
STEEL:
1    X=   2.5  Y=   2.5  A=0.79   T= 1 :  Long. Steel Type
3    X=  21.5  Y=   2.5  G= 1, 3       :  8 #8 Bars
5    X=  21.5  Y=  21.5  G= 3, 5       :  2 in. clear cover to bars
7    X=   2.5  Y=  21.5  G= 5, 7       :  assume #4 hoops
8    X=   2.5  Y=  12.0                :
:
PROPERTY:
I=2  FC=12*.85  E=5400   :
I=2 FC=11.2 E=5400  FY=60  FM=0.3 RL=0.0174 RP=0.02061 
     N=8  D=1  DT=0.5  H=18  S=2  :
FY=60  E3=0.120  E=29000          : Fracture of steel at 12% strain
:
DATA:
EC=0.003  A=-45  N=20 : Moment about global X-axis for Ultimate
EC=0.003  A=-45  N=20  PHI=0.70 : compressive strain of 0.003, with and
:                               without capacity reduction factors
:
END
